The work function for the surface of aluminium is 4.2 eV. How much potential difference will be required to stop the emission of maximum energy electrons emitted by light of `2000 overset(@)(A)`wavelength?What will be the wavelength of that incident light for which stopping potential wil be zero?

The work function of caesium is 2.14 eV. Find the wavelength of the incident light if photocurrent is brought to zero by stopping potential of 0.60 V.

The work functions for potassium and caesium are 2.25 eV and 2.14 eV respectively. Will the photoelectric effect occur for either of these elements with light of wavelength 5180 overset(@)(A)

A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm . The retarding potential required to stop the escape of photo - electrons is

The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?

An electron of work function 1.4 eV is emitted with a velocity 5 xx 10^6 m/s .The wavelength of the incident radiation is

The work function for potassium and caesium is 2.25 eV and 2.14 eV, respectively. Will the photoelectric effect occur for either of these elements, With incident light of wavelength 5650overset@ A

When a metal surface is illuminated by a monochromatic light of wave-length lambda , then the potential difference required to stop the ejection of electrons is 3V . When the same surface is illuminated by the light of wavelength 2lambda , then the potential difference required to stop the ejection of electrons is V . Then for photoelectric effect, the threshold wavelength for the metal surface will be