Energy of the electron in the ground state of hydrogen atom is `(-13.6eV)`. Calculate the energy in `3^(rd)` and `4^(th)` orbit.

Energy of an electron in ground state of hydrogen atom is -13.6eV . Calculate its K.E. and P.E. in the same state.

The energy of an electron in the 1st Bohr orbit of hydrogen atom is

The energy in the ground state of hydrogen atom is -13.6 eV , then energy of 1st excited state is

The energy of the electron in the ground state of hydrogen atom is -13.6 eV . Find the Rydberg's constant and the wavelength of the first line of Paschen series

Find the velocity of the electron in the ground state of hydrogen atom.Hence find the velocities when the electron is in the second and fourth orbit.(Radius of the first Bohr orbit = 0.53xx10^-10m , mass of electron= 9.1xx10^-31 kg )

Energy in the ground state of normal H-atom is -13.6 eV .Calculate its kinetic energy and potential energy.

The energy of an electron in an excited state of hydrogen atom is -1.51 eV . Calculate the angular momentum of the electron in this state. h = 6.63 xx 10^-34 Js

Energy of an electron in the first Bohr orbit is -13.6eV. Hence calculate the energy of the electron in second orbit.

Find the velocity of the electron in the first orbit in hydrogen atom. Hence, find velocities when electron is in 3rd and 5th orbit.

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4eV . What is the potential energy of the electron in this state?