In a transistor doping level in base is increased slightly. How will it affect
collector current

In a transistor doping level in base is increased slightly. How will it affect base current

The input resistance of a transistor is 1000 Omega . On changing its base current by 10 muA , the collector current increases by 2 mA. If a load resistance of 5 k Omega is used in the circuit, calculate : the current gain.

The input resistance of a transistor is 1000 Omega . On changing its base current by 10 muA , the collector current increases by 2 mA. If a load resistance of 5 k Omega is used in the circuit, calculate :voltage gain of the amplifier.

A change of 0.04 V takes place between the base and the emitter when an input signal is connected to the CE transistor amplifier. As a result, 20 muA change takes place in the base current and a change of 2 mA takes place in the collector current. Find the input resistance and A.C. current gain.

In npn transistor, if I_E = emitter current, I_B = base current and I_C = collector current, then

For a transistor in common emitter configuration the current amplification factor is 4 .If the change in base current be 6 mA, Then the change in collector current will be

Why is the base of a transistor made thin and is lightly doped?

In a common-base connection, a certain transistor has an emitter's current of 10 mA and a collector's current of 9.8 mA. Calculate the value of the base current.

In p-n-p transistor the base current is 1mA and the collector current is 10mA . The emitter current is

A transistor is used as a common emitter amplifier with a load resistance 2 kOmega . The input resistance is 150 Omega . Base current is changed by 20 muA which results in a change in collector current by 1.5 mA. The voltage gain of the amplifier is