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The reduction potential of hydrogen half...

The reduction potential of hydrogen half cell will be negative if :

A

`p(H_(2))=1 "atm and "[H^(+)]=1.0M`

B

`p(H_(2)) =2"atm and "[H^(+)]=1.0M`

C

`p(H_(2)) =2"atm and "[H^(+)]=2.0M`

D

`p(H_(2))=1"atm and "[H^(+)]=2.0M`

Text Solution

Verified by Experts

The correct Answer is:
B
For hydrogen electrode,
`H^(+)(aq) +e^(-) to (1)/(2) H_(2)(g) rArr E=E^(@) -(0.0591)/(n)"log"((p_(H_(2)))^(1//2))/([H^(+)])`
Here, n = number of electrons involved in the reaction `E=E^(@) -(0.0591)/(1)"log" ((p_(H_(2)))^(1//2))/([H^(+)])`
`E= -0.0591"log"((P_(H_(2)))^(1//2))/([H^(+)])" " [ :. E^(@)=0 " for H" - "electrode"] rArr ` E will be -ve when `((P_(H_(2)))^(1//2))/([H^(+)])` is +ve.
i.e., `(P_(H_(2)))^(1//2) gt [H^(+)]`

Hence, when is 2 atm and `[H^(+)]` is 1.0 M, `E_("red")` is negative.
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