CBSE#!#Divisibility Rules of 4,8,7,11,13

If the 6-digit number 479xy9 is divisible by each of 7,11,13, then (x-y) is equal to -

Show that 2^(125)+3^(105) is divisible by 5,7,11,25 but not by 13.

If the number 4 8 3 0 7 * 8 is divisible by divisible by 11, then the missing digit (*) is

Which among the following numbers is exactly divisible by 7,11 and 13 ?

Which among the given numbers are exactly divisible by 7, 11 and 13?

325325 is a six-digit number.It is divisible by 7 only (b)11 only (c)13 only (d) all 7,11 and 13

Which among the following numbers is exactly divisible by 7, 11 and 13? निम्नलिखित में से कौन सी संख्या 7, 11 और 13 से पूर्णतः विभाज्य है?

If the six-digit number 479 xyz is exactly divisible by 7, 11 and 13, then {( y + z) :x} is equal to :

If a number is divisible by both 11 and 13, then it must be necessarily 429 (b) divisible by (11xx13)(c) divisible by (11+13)(d) divisible by (13-11)