A particle moving along a straight line is at a distance S from a point O on the line in time t, where `S = t^3-6t^2+8t+5`
Find the velocity when the acceleration is `12 cm//sec^2`

A particle moves along a straight line according to the law of motion S = at^2+bt+c if at end of 3 seconds, it has covered 20 cms, attained velocity 9cm//sec and has acceleration 4cm//sec^2 , find a,b,c.

The displacement equation of a particle moving along a straight line with uniform acceleration is x = v_0t + 1/2at^2 . Find the distance covered by the particle in the last second of its motion.

Find the distance of the point (-3,4) from the line 12x-5y+2=0

A particle moves along a straight line according to x = Pt^2 + 2qt + r where x is the distance travelled in time t and p, q and r are constants. Find an expression for the acceleration of the particle.

A particle describes a distance x m in t sec, given by x = 4+5t+63t^3 . Find the velocity of the particle at the end of 2 secs and the acceleration at the end of 3 secs

Find the distance of the point (6, 2, -5) from the plane 2x + 3y - 2z = 8.

The distance x cm traversed by a particle along a straight line in t seconds is given by x = 2t^3 - 15t^2+36t+6 At what time will the velocity of the particle is minimum?

An object is moving along a straight line with a uniform speed of 10m/s. Plot a graph showing distance versus time from t=0 to t=10s.

The initial velocity of a particle moving along straight line is 20 m/s and its retardation Is 2 m/s_2. The distance moved by the particle in the fifth sec. of its motion is :

Find the relation v = u + at , where, u-initial velocity, v-final velocity, a-acceleration and t-time.