A parallel plate capacitor has a capacity of `6 muF` (Micro farad), with air in between the plates and `60 muF ` (Micro farad) when dielectric medium is introduced.What is the dielectric Constant (K ) of the medium ?

Calculate the area of plates of a capacitor of capacity 2muF , with separation 1.77 mm between the plates.

Calculate the area of plates of a capacitor of capacity 2muF , with separation 1.77 mm between the plates.

A parallel plate capacitor has a capacitance of 2muF . A slab of dielectric constant 5 is inserted between the plates and the capaitor is charged to 100 V and then isolated. What is the new potential difference, if the dielectric slab is removed?

In a parallel plate capacitor, the capacitance increases from 4 muF to 80muF no introduicng a dielectric medium between the plates. What is the dielectric constant of the medium?

A parallel plate capacitor has a capacitance of 2muF . A slab of dielectric constant 5 is inserted between the plates and the capaitor is charged to 100 V and then isolated. How much work is required to remove the dielectric slab?

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the capacitance

A parallel plate capacitor with air between the plates has a capacitance of 8 pF. The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant K. Calculate the value of the capacitance of the capacitor in the second case.

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the energy density of the capacity of change.

On charging a parallel plate capacitor to a potential V, the spacing between the plates is halved and a dielectric medium of k = 10 is introduced between the plates, without disconnectign the d.c. source. Explain, using the suitable expressions, how the electric field

A parallel plate capacitor with air between the plates has capacitance of 9pF. The separation between its plates is 'd'. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant k_1=3 and thickness d/3 while the other one has dielectric constant k_2=6 and thickness (2d)/(3) . Capacitance of the capacitor is now