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MBD-Number Systems-Exercise
- Solve the following equation : (sqrt6)^8 div (sqrt6)^5=6^x.
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- Rational number 3/40 is equal to :
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- A rational number between 3 and 4 is :
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- A rational number between 3/5 and 4/5 is :
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- On rationalising the denominator of 1/(2+sqrt3) we get :
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- On rationalising the denominator of 1/(sqrt3-sqrt2) we get :
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- The exponent form of root(3)(7) is :
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- The exponent form of root(8)(61/1123) is :
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- The value 64^(1/2) is :
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- The value 32^(1/5) is :
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- The value 125^(1/3) is :
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- The value 9^(3/2) is :
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- The value 32^(2/5) is :
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- The value 16^(3/4) is :
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- The value 125^-(1/3) is :
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- 2^(2/3)*2^(1/5) equals to :
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- 11^(1/2)/11^(1/4) equals to :
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- The smallest natural number is :
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- The value of 16^17 div 16^15 is equal to :
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- The value of 25^-(1/2) is :
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