Home
Class 9
MATHS
DeltaABC and DeltaDBC are two isosceles ...

`DeltaABC` and `DeltaDBC` are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig.
).If AD is extended to intersect BC at P, show that AP bisects `angleA` as well as `angleD`.

Promotional Banner

Topper's Solved these Questions

  • Surface Areas and Volumes

    MBD|Exercise Exercise|226 Videos

Similar Questions

Explore conceptually related problems

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that DeltaABP ~= DeltaACP .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that DeltaABP ~= DeltaACP .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that DeltaABD ~= DeltaACD .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that DeltaABD ~= DeltaACD .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

ABC and DBC are two isosceles triangles on the common base BC. Then :

ABC and DBC are two isosceles triangles on the common base BC. Then :

ABC and DBC are two isosceles triangles are same base BC. Show that angleABD=angleACD

ABC and DBC are two isosceles triangles on the same base BC (See Fig. ). Show that angleABD = angleACD .

MBD-Triangles-Exercise
  1. DeltaABC and DeltaDBC are two isosceles triangles on the same base BC ...

    Text Solution

    |

  2. DeltaABC and DeltaDBC are two isosceles triangles on the same base BC ...

    Text Solution

    |

  3. DeltaABC and DeltaDBC are two isosceles triangles on the same base BC ...

    Text Solution

    |

  4. DeltaABC and DeltaDBC are two isosceles triangles on the same base BC ...

    Text Solution

    |

  5. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show ...

    Text Solution

    |

  6. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show ...

    Text Solution

    |

  7. Two sides AB and BC and median AM of one triangle ABC are respectively...

    Text Solution

    |

  8. Two sides AB and BC and median AM of one triangle ABC are respectively...

    Text Solution

    |

  9. BE and CF are two equal altitudes of a triangle ABC. Using RHS congrue...

    Text Solution

    |

  10. ABC is an isosceles triangle with AB = AC. Draw AP bot BC to show that...

    Text Solution

    |

  11. P is a point equidistant from two lines l and m intersecting at point ...

    Text Solution

    |

  12. The image of an object placed at a point before a plane mirror LM is s...

    Text Solution

    |

  13. Show that in a right angled triangle, the hypotenuse is the longest si...

    Text Solution

    |

  14. In Fig. , sides AB and AC of DeltaABC are extended to points P and Q ...

    Text Solution

    |

  15. In Fig. , angleB < angleA and angleC < angleD. Show that AD < BC.

    Text Solution

    |

  16. In DeltaABC, BC = 3.6 cm, CA = 2.8 cm. AB = 3.4 cm, arrange the angles...

    Text Solution

    |

  17. In DeltaABC if angleA = 48^@, angleB = 51^@, find the third angle and ...

    Text Solution

    |

  18. In DeltaABC if angleA = angleB=62frac(1^@) 2, find the third angle and...

    Text Solution

    |

  19. In the Fig. If AB = AD. Prove that AB > CD.

    Text Solution

    |

  20. ABC is an equilateral triangle. X is point on AC, Prove that BX > XC a...

    Text Solution

    |