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AD is an altitude of an isosceles triang...

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that:- AD bisects `angle A`.

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MBD-Triangles-Exercise
  1. DeltaABC and DeltaDBC are two isosceles triangles on the same base BC ...

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  2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show ...

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  3. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show ...

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  4. Two sides AB and BC and median AM of one triangle ABC are respectively...

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  5. Two sides AB and BC and median AM of one triangle ABC are respectively...

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  6. BE and CF are two equal altitudes of a triangle ABC. Using RHS congrue...

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  7. ABC is an isosceles triangle with AB = AC. Draw AP bot BC to show that...

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  8. P is a point equidistant from two lines l and m intersecting at point ...

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  9. The image of an object placed at a point before a plane mirror LM is s...

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  10. Show that in a right angled triangle, the hypotenuse is the longest si...

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  11. In Fig. , sides AB and AC of DeltaABC are extended to points P and Q ...

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  12. In Fig. , angleB < angleA and angleC < angleD. Show that AD < BC.

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  13. In DeltaABC, BC = 3.6 cm, CA = 2.8 cm. AB = 3.4 cm, arrange the angles...

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  14. In DeltaABC if angleA = 48^@, angleB = 51^@, find the third angle and ...

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  15. In DeltaABC if angleA = angleB=62frac(1^@) 2, find the third angle and...

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  16. In the Fig. If AB = AD. Prove that AB > CD.

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  17. ABC is an equilateral triangle. X is point on AC, Prove that BX > XC a...

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  18. In given Fig. , ABC is a triangle with base BC. If the base angles of...

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  19. In DeltaABC, AC > AB and AD is a median. Prove that angleBAD < angleCA...

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  20. In fig. BP and CP are the bisectors of angleB and angleC respectivel...

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