ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that `Delta APB ~= Delta CQD`.

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that AP = CQ.

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that AP = CQ.

ABCD is a parallelogam and AP and CQ are the perpendicualr form vertices A and C on diagonal Show that: AP=CQ

ABCD is a parallelogam and AP and CQ are the perpendicualr form vertices A and C on diagonal Show that: triangleAPBequivtriangleCQD

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. ) Show that Delta AQB ~= Delta CPD .

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. ) Show that Delta AQB ~= Delta CPD .

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. ) Show that Delta APD ~= Delta CQB .

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. ) Show that Delta APD ~= Delta CQB .

Line l is the bisector of an angle angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A (see Fig. 7.20). Show that: (i) triangle APB cong triangle AQB (ii) BP = BQ or B is equidistant from the arms of angle A .