Home
Class 9
MATHS
In Fig. , P is a point in the interior ...

In Fig.
, P is a point in the interior of a parallelogram ABCD. Show that `ar(APB)+ar(PCD)=1/2ar(ABCD)`.

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

In Fig. the area of parallelogram ABCD is :

In Fig. the area of parallelogram ABCD is :

If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar(EFGH) =1/2 ar(ABCD).

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC).

O is any point on the diagonal PR of a parallelogram PQRS. Prove that : ar(PSO) = ar(PQO)

ABCD, DCFE and ABFE are parallelograms. Show that ar(ADE) = ar(BCF)

The area of the parallelogram ABCD is 90 cm^2 Find ar(ABD)

In fig. P is the mid point of side BC of a parallelogram ABCD such that angleBAP=angleDAP prove that AD=2CD