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D and E are points on sides AB and AC respectively of `DeltaABC` such that ar (DBC) = ar (EBC). Prove that `DE II BC`.

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MBD-Areas of Parallelograms and Triangles-Exercise
  1. In Fig. diagonals AC and BD of quadrilateral ABCD intersect at O su...

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  2. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a w...

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  3. D and E are points on sides AB and AC respectively of DeltaABC such th...

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  4. XY is a line parallel to side BC of triangle ABC. If BE II AC and CF I...

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  5. Find x+y+z

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  6. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a w...

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  7. Find x+y+z

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  8. D and E are points on sides AB and AC respectively of a DeltaABC such ...

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  9. Determine a triangle equal in area to a given quadrilateral.

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  10. ABCD is a parallelogram whose diagonals intersect at E. AC is produced...

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  11. Find x+y+z

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  12. Parallelogram ABCD and rectangle ABEF are on the same base AB and have...

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  13. In the above figure both RISK and CLUE are parallelograms. Find the va...

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  14. Find x+y+z

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  15. In fig., find tan P - cot R.

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  16. In Fig. , ABC and BDE are two equilateral triangles such that D is th...

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  17. In Fig. , ABC and BDE are two equilateral triangles such that D is th...

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  18. In Fig. , ABC and BDE are two equilateral triangles such that D is th...

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  19. In Fig. , ABC and BDE are two equilateral triangles such that D is th...

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  20. In Fig. , ABC and BDE are two equilateral triangles such that D is th...

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