. 540 gram of ice at `0^@C` is mixed with 540 gram of water at `80^@C`. The final temperature' of the mixture is

One gram of ice at 0^@C is added to 5 gram of water at 10^@C . Final temperature of the mixture is

One gram of ice is mixed with one gram of steam. At thermal equilibrium the temperature of the mixture is

2 kg water at 80^@C is mixed with 3 kg water at 20^@C . Assuming no heat losses, find the final temperature of the mixture

When 0.15 kg of ice at 0^@C mixed with 0.30 kg of water at 50^@C in a container, the resutling temperature is 6.7^@C . Calculate the latent heat of fusion of ice. Given S_(water) = 4186J kg^-1 K^-1 .

200 gram of a solid ball at 20^@C is dropped in an equal amount of water at 80^@C . The resulting temperature is 60^@C . This means that specific heat of solid is-

When 0.2 kg of ice at 0°C is mixed with 0.40 kg water at 50°C,the resulting temperature is 7°C,Find latent heat of fusion of ice,(Give s-w=4186 Jkg^-1 K^-1)

What is the physical state of water at 0^@C

75 g of water at 100^@ C is added to 20 g of ice at -15^@C . Calculate the resulting temperature, give that latent heat of ice= 80 cal g^(-1)C^(-1) and specific heat of ice=0.5 cal g^(-1) C^(-1) .

In an experiment on the specific heat of a metal, a 0.20 kg block of the metal at 150^@C is dropped in a copper calorimeter (of water equivalent 0.025 kg) containing 1-50 cm^3 of water at 27^@C . The final temperature is 40^@C . Compute the specific heat of the metal. If heat losses to the surroundings are not negligible, is your answer greater or smaller than the actual value for specific heat of the metal?

A hot ball of iron weighing 200 g is dropped into 500 g water at 10°C .The resulting temperature is 22.8°C .Calculate the temperature of the ball