The angular displacement of a particle performing circular motion is `theta = (t^3)/60 - t/4` where `theta` is in radian and 't' is in seconds. Then the angular velocity and angular accleration of the particle at the end of 5 s will be

Options

A. `1 rad//s, 5 rad//s^2`
B. `1 rad//s, 0.5 rad//s^2`
C. `5 rad//s, 1 rad//s^2`
D. `0.1 rad//s, 5 rad//s^2`