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The amount of work performed to break a ...

The amount of work performed to break a shperical drop of radius 1 mm into million drops of equal radius , is
`(T=7.2xx10^-2N//m)`

A

`9xx10^-5 J`

B

`90xx10^-5 J`

C

`9xx10^-6 J`

D

`9xx10^-7 J`

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