Home
Class 12
PHYSICS
The radius of a soap bubble is reduced f...

The radius of a soap bubble is reduced from 5 cm to 1 cm. Then the change in surface energy of the bubble is.(T=0.02 N/m)

A

`1xx10^-3 J`

B

`1.2xx10^-3 J`

C

`2.4xx10^-3 J`

D

`2.8xx10^-3 J`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the work done in increasing the radius of a soap bubble in air from 2 cm to 3 cm. The surface tension of soap solution is 25 dyne/cm.

Calculate the work done in increasing the radius of a soap bubble in air from 1 cm to 2 cm. The surface tension of soap solution is 30 dyne/cm . (pi = 3.142)

Twenty seven droplets of water, each of radius 0.1 mm coalesce into a single drop. Find the change in surface energy. Surface tension of water is 0.072 N//m .

Twenty seven droplets of water , each of radius 1.1 mm coalesce into a single drop .Find the change in surface energy. Surface tension of water is 0.072 N/m.

Eight droplets of water, each of radius 0.2 mm, coalesce into a single drop . Find the change in total surface energy. (Surface tension of water = 0.072 N/m)

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

Calculate the work done in blowing a soap bubble to a radius of 1 cm. The surface tension of soap solution is 2.5 xx 10^-2 N//m .

The work done in blowing a soap bubble from a radius of 6 cm to 9 cm if surface tension of soap solution is 25xx10^(-3) N//m , is