`H^(+),He^(+)` and `O^(2+)` all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity. The masses of `H^(+), He^(+)` and `O^(2+)` are 1 amu, 4 amu, and 16 amu respectively. Then :

H^(+), He^(+) and O^(++) all having the same kinetic energy pass through a region in which there is a uniform magnetic field perpendicular to their velocity . The masses of H^(+), He^(+) and O^(2+) are 1 amu, 4 amu and 16 amu respectively . Then

If an alpha particle and an electron have the same kinetic energy. Which undergoes the greater deflection when passed through a magnetic field?

Calculate the energy released in MeV during the reaction ._(3)^(7)Li + ._(1)^(1)H to 2[._(2)^(4)He] if the masses of ._(3)^(7)Li, ._(1)^(1)H and ._(2)H_(4)He are 7.018, 1.008 and 4.004 amu respectively.

Mixed He^(+) and O^(2+) ions (mass of He^(+) =4 amu and that of O^(2+)=16 amu) beam passes a region of constant perpendicular magnetic field. If kinetic energy of all the ions is same then

Two ions of masses 4 amu and 16 amu have charges +2e and +3e respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then :

An alpha particle (mass = 4amu) and a singly charged sulfur ion (mass 32 amu) are initially at rest. They are accelerated through potential V and then allowed to pass into a region of uniform magnetic field which is normal to velocities of the particles. Within this region the alpha particle and the sulfur ion move in circular orbits of radii r_a and r_s resp. The ratio (r_s/r_a) is

An electron, a proton and a He^(+) ion projected into a magnetic field with same kinetic energy, with velocities being perpendicular to the magnetic field. The order of the radii of circles traced by them is :