Calculate the total heat required heat it to `100^@C`.Given `Delta_(fus)H^0(ice)=6.01KJmol^-1 at 0^@C,Delta_(vap)H^0(H_2O)=40.7KJmol^-1 at 100 ^@C` specific heat of water is `4.18 J g^-1K^-1`

Calculate the total heat required (a) to melt 180 g to ice at O^@C (b) heat it to 100^@C and then (c) vaporise it at that temperature. Given Delta_(fus) H^@ (d) = 6.01kjmol at O^@C Delta vap H_(H2O) = 40.7 kjmol at 100^ O^@C @C Specific heat of water

A calorimeter of mass 50 gm and specific heat capacity 0.42 J g^-1 ^@C^-1 contains some water at 20^@ C. A metal piece of mass 20 gm at 100^@ C is dropped into the calorimeter. After stirring, the final temperature of the mixture is found to be 22^@C .Find the mass of water used. (specific heat of metal piece= 0.3 J g^-1 ^@C^-1 specific heat of water = 4.2 J g^-1 ^@C^-1 )

60 g of ice at 0^@C is mixed with 60 g of steam at 100^@C . At thermal equilibrium, the mixture contains (Latent heat of steam and ice are 540 g^-1 and 80 cal g^-1 respectively, specific heat of water = 1cal g^-1^@C^-1 )

The water equivalent of a calorimeter is 10 g and it contains 50 g of water at 15^@C . Some amount of ice, initially -10^@C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice = 0.5 cal g^-1^@C^-1, specific heat of water = 1.0 cal g^1^@C^-1 and latent heat of melting of ice =80 cal g^-1 )?