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Let ABCD be a square. An arc of a circle...

Let ABCD be a square. An arc of a circle with A as centre and AB as radius is drawn inside the square joining the points B and D. Points P on AB, S on AD, Q and R on arc BD are taken such that PQRS is a square. Further suppose that PQ and RS are parallel toAC. Then, `(area PQRS)/(area ABCD)` is

A

`1/8`

B

`1/5`

C

`1/4`

D

`2/5`

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