Vapour Pressure of Two Volatile Liquids

Solution of two volatile liquids x and y obey Raoult's law. At a certain temperature it is found that when the total pressure above a given solution is 400 mm of Hg , the mole fraction of x in the vapour is 0.45 and in the liquid is 0.65 . What are the vapour pressures of two pure liquids at the given temperature?

The vapour pressure of high b.pt. liquids is……..then the vapour pressure of a low boiling liquid:

Vapour Pressure OF Solution and Liquid Composition Curve || Relation between Mole Fraction in Liquid Phase and Vapour Phase || Vapour and Liquid Composition Curve

Vapour pressure diagram of some liquids plotted against temperature are shown below Most volatile liquid

A solution of two volatile liquids A and B obeys Raoult's law. At a certain temperature it is found that when the pressure above the mixture in equilibrium is 402.5 mm of Hg, the mole fraction of A in the vapour is 0.35 and in the liquid it is 0.65. What are the vapour pressures of two liquids at this temperature ?

The vapour pressure of a mixture of two volatile liquids is given by P_(M) = 4.0X_(A)+3.0 . Find the vapour pressure of pure B .

The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is