In `Delta ABC and Delta DEF`, we have `(AB)/(DE)=(BC)/(EF)=(AC)/(DF)=5/7`, then `ar (Delta ABC) : ar (Delta DFR) =?`

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

In Delta ABC and Delta DEF is (AB)/(DE) = (BC)/(DF) then they will be similar if:

It is given that Delta ABC - Delta PQR , with (BC)/(QR) = (1)/(4) . Then (ar Delta PQR)/(ar Delta ABC) is equal to:

In Delta ABC and Delta DEF , if AB = EF, BC= DE and CA = FD, then

If Delta ABC~Delta DEF such that 2AB=DE and BC=6 cm find EF.

If Delta ABC and Delta DEF are similar and 2AB = DE , BC = 8 cm , then calculate EF.

It is given that Delta ABC~Delta PRQ and (BC)/(QR)=(2)/(3) " then " (ar (Delta PQR))/(ar (Delta ABC))=?

Which of the following pairs of triangles are congruent ? In each case, state the condition of congruency : (a) In Delta ABC and Delta DEF , AB = DE, BC = EF and angle B = angle E . (b) In Delta ABC and Delta DEF, angle B = angle E = 90^(@) , AC = DF and BC = EF. (c) In Delta ABC and Delta QRP , AB = QR, angle B = angle R and angle C = angle P . (d) In Delta ABC and Delta PQR , AB = PQ, AC = PR and BC = QR. (e) In Delta ABC and Delta PQR , BC = QR, angle A = 90^(@), angle C = angle R = 40^(@) and angle Q = 50^(@) .