Recommended Questions
- विवेचकावरून वर्गसमीकरणांच्या मुळांचे स्वरूप ठरवा. 2x^(2) - 5x + 7= 0
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- Solve 5x-2(2x-7)=2(3x-1)+7/2
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- 5x - 7 y - 5 =0 , 2x + ky - 1 =0
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- Determine nature of roots of the quadratic equation 2x^2-5x+7 =0
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- हल कीजिए : 5x-2(2x-7)=2(3x-1)+(7)/(2)
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- I : The 2x+ky-10=0, 5x+2y-7=0 are parallel then k = 4. II : If 2x+ky...
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- If y = (5x +7)/(2x -3) then y (2) =
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- Evaluate int(0)^(1)(2x+7)/(5x^(2)+9) dx,
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- Solve 5x-2(2x-7)=2(3x-1)+7/2
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