A simple harmonic oscillator has amplitude 2 A and maximum velocity 2 V. Then its displacement at which its velocity is V and the velocity at displacement A are

A particle is executing S.H.M. with amplitude 'A' and maximum velocity V_(m) . The displacement at which its velocity is half of the maximum velocity is

A simple harmonic motino has amplitude A and time period T. The maxmum velocity will be

The amplitude of a particle performing SHM is 'a'. The displacement at which its velocity will be half the maximum velocity is

In the previous problem, if initial velocity is v_(0) , then velocity and displacement will be

A particle executes a S.H.M. of amplitude A and maximum velocity V_(m) then its speed at displacement A//2 is

If a particle executing S.H.M. with amplitude A and maximum velocity vo, then its speed at displacement A/2 is

A simple harmonic oscillator has amplitude A, angular velocity omega , and mass m . Then, average energy in one time period will be

A body executing linear simple harmonic motion has a velocity of 3 cm/s when its displacement is 4 cm and a velocity of 4 cm/s when its displacement is 3 cm. Then amplitude of oscillation with be

A body of mass 40g is executing linear simple harmonic motion and has a velocity of 2cm/s when its displacement is 3cm and a velocity of 3 cm/s when its displacement is 2cm . Then

A particle is executing SHM with amplitude 4 cm and has a maximum velocity of 10 cm/sec What is its velocity at displacement 2 cm?