Find value of c such that line joining the points (0, 3) and (5, -2) is a tangent to curve `y=c/(x+1)

Find value of c such that line joining the points (0,3) and (5,-2) becomes tangent to curve y=(c)/(x+1)

Find value of c such that line joining points (0, 3) and (5, -2) becomes tangent to y=(c)/(x+1) .

The line joining the points (0,3) and (5,-2) becomes tangent to the curve y=c/(x+1) then c=

If the line joining the points (0,3) and (5,-2) is a tangent to the curve y=(C)/(x+1), then the value of c is 1(b)-2(c)4(d) none of these

Find the value of y if the line joining the points (3, y) and (2, 7) in parallel to the line joining the points (-1, 4) , (0, 6) .

Determine the values of x and y so that the line joining the points A(x,3,11),B(1,1,-2) is parallel to the line joining the points C(2,5,3),D(-4,y,-6).

If the line joining the points (5,y) and (4,9) is parallel to the line joining the points (0,5) and (1,7) , find the value of y .

Find the value of c so that the point (3,c) lies on the line represented by 2x-3y+5=0.