Two simple harmonic motions are represented as `y_(1)=10 "sin" omegat " and "y_(2)=5 "sin" wt +5 "cos" omega t`
The ratio of the amplitudes of `y_(1) " and " y_(2)` is

Two simple harmonic motions are represented as y_(1)=10 "sin" omega " and "y_(2)=5 "sin" wt +5 "cos" omega t The ration of the amplitudes of y_(1) " and " y_(2) is

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Two simple harmonic motions are given by y _(1) = 5 sin ( omegat = pi //3). y_(2) = 5 ( sin omegat+ sqrt(3) cos omegat) . Ratio of their amplitudes is

Two simple harmonic motions are represented by the equations y_(1) = 8 sin(pi)/(4)(10t + 2),y_(2) = 6(sin 5pit + sqrt(3) cos 5omegat) IF the ratio of amplitudes of y_(1) and y_(2) is alpha and their respective ratio of time periods is beta , then find beta//alpha .

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two simple harmonic motion, are represented by the equations y _(1) = 10 sin ( 3 pi t + (pi)/(3)) y _(2) = 5 ( sin 3 pi t + sqrt3 cos 3 pi t ) Ratio of amplitude of y _(1) to y _(2) = x :1. The value of x is __________

Two SHM's are represented by y_(1) = A sin (omega t+ phi), y_(2) = (A)/(2) [sin omega t + sqrt3 cos omega t] . Find ratio of their amplitudes.

Two simple harmonic motions are represented by y_(1)=4sin(4pit+pi//2) and y_(2)=3cos(4pit) . The resultant amplitude is