(sqrtx3+sqrtx2)(\sqrt{3}-sqrtx2)=(sqrtx3...

(sqrtx3+sqrtx2)(\sqrt{3}-sqrtx2)=(sqrtx3)^2-(sqrtx2)^2=3-2=1Using this, find the aproximate values of 1(sqrtx3+sqrtx2) "and 1(sqrtx3-sqrtx2) correct to two décimal: places.(sqrtx3 \approx 1.732, sqrtx2 \approx 1.414)

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