The perpendicular from the square corner of a triangle cuts the Opposite side into two parts of 2 and 3 centimetres length.'(##VPU_HSS_MAT_IX_C07_E01_001_Q01##)'
i) Prove that the two small triangles cut by the perpendictlar have the same angles.
ii) Taking the length-of the perpendicular as 'h', prove that 'h2=3~h'.
iii) Calculate-the perpendicular sides the large triangle.
in) Prove that if the perpendicular from the square comer of a triangle divided the opposite side into parts of lengths a and 'mathbffb' and if the length of the perpendicular is 'h', then 'h^2=' ab.