How much is `angle A C E` in this figure?
'(##VPU_TTT_MAT_VII_C01_E01_014_Q01##)'

Explanation

Since `angle` ACE and `angle B C E` form a linear palr, the sum of the angles is `180^(circ)`.
`angle B C E =angle B C D+angle D C E `

`=25^(circ)+50^(circ) `
`=75^(circ) `
therefore `angle A C E =180^(circ)-angle B C E`
`=180^(circ)-75^(circ) =105^(circ)`

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