evaluate 1) `5^2 xx 8^2` 2) `2.5^2 xx 4^2` 3) `(1.5)^2 xx(0.2)^2`

(2/3)^3 xx(2/3)^5

1 (1)/(2) xx 6 (2)/(3)

5^(1) xx 5^(3) xx 5^(5) xx ….5^(2n-1) = (25)^(72) Find n.

Find 'n' in the equation 2 xx 2^(3) xx 2^(5) xx….xx 2^(n) = (0.125)^(-27)

Show that (1 xx 2^2+2 xx 3^2+. .+n xx(n+1)^2)/(1^2 xx 2+2^2 xx 3+. .+n^2(n+1))=(3 n+5)/(3 n+1)

Caiculate the products below: i) 46.2 xx 0.23 ii) 57.52 xx 31.2 iii) 0.01 xx 0.01 iv) 2.04 xx 24 v) 2.5 xx 3.72 vi) 0.2 xx 0.002

2 (3)/(4) xx (5)/(8)