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A body of mass 5kg moves according to th...

A body of mass `5kg` moves according to the relation `x=t^(2)+2t^(3)` .The power used by the body at `t=2s` is?

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Under to action of constant force F =10 N, a body moves in a straight line so that the relation between the distance S moved by the body and the time t is described by the equation S =A -Bt +Ct^(2) Find the mass of the body if C =1 m//s^(2) .

Knowledge Check

  • A boat of mass 300 kg moves according to the equation x= 1.2t^(2) - 0.2 t^(3) . When the force will become zero ?

    A
    2s
    B
    1s
    C
    6s
    D
    2.8 s

  • A body o fmass 6 kg moves in a staight line according to the equation x= t^(3)-75t , where x denotes the distance in metre and t the time in second. The force on the body at t=4s is

    A
    64 N
    B
    72 N
    C
    144 N
    D
    36 N

  • A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-2) , p = 3 ms^(-1) and r = 5 ms^(-3) . The force acting on the body at t = 2s is

    A
    136 N
    B
    134 N
    C
    158 N
    D
    68 N

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    A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

    The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its velocity at t = 2s.

    The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its acceleration at t = 4s.

    A body of mass 2kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where p = 3ms^(-1),q = 4 ms^(-2) and r = 5ms^(-3) .

    A simple pendulu has a time period T_(1) . The point of suspension of the pendulum is moved upword according to the relation y= (3)/(2)t^(2) , Where y is the vertical displacement . If the new time period is T_(2) , The ratio of (T_(1)^(2))/(T_(2)^(2)) is ( g=10m//s^(2))

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