If a rocket is fired with a velocity, `V=2sqrt(gR)` near the earth's surface and goes upwards, its speed in the inter-stellar space is

If a rocket is fired with a velocity, V=2sqrt(2gR) near the earth's surface and goes upwards, its speed in the inter-stellar space is

A rocket is fired with a speed v = 2 sqrt (gR) near the earth's surface and directed upward, what is intersteller speed of rocket v^' , where v_e escape speed on the surface of earth

A rocket is fired with a speed, v=2sqrt(gR) , near the earth's surface and directed upwards. (a) Show that it will escape from the earth. (b) Show that in interstellar space its speed is v=sqrt(2gR) .

A rocket is fired with a speed v=2sqrt(gR) near the earth's surface and directed upwards. (a) Show that it will escape from the earth. (b) Show that in interstellar space its speed is v=sqrt(2gR) .

A rocket is fired with a speed u=3sqrt(gR) from the earth surface . What will be its speed at interstellar space ?

If a body is projected with speed v greater than escape speed v_(e) from the surface of earth, find its speed in intersteller space.

A rocket is accelerated to speed upsilon = 2sqrt(gR) near the earth's surface ( R = radius of earth). Show that very far from earth its speed will be upsilon = sqrt(2gR) .

STATEMENT-1 : A particle is projected with a velocity 0.5sqrt(gR_(e )) from the surface of the earth at an angle of 30^(@) with the vertical (at that point ) its velocity at the highest point will be 0.25sqrt(gR_(e )) because STATEMENT-2 : Angular momentum of the particle earth system remains constant.

A particle is fired vertically upward fom earth's surface and it goes up to a maximum height of 6400 km. find the initial speed of particle.

If a body is thrown at speed of triple as that of escape speed (V_e) from earth s surface, then at what speed it will move in interstellar space?