When two spheres of equal masses undergo glancing elastic collision with one of them at rest after collision they will move

Assertion : When two equal masses undergo a glancing elastic collision with one of them at rest then after the collisioin, they will move at 90^(@0 to eachtoerh. Reason : It follows from the principle of conservation of linear momentum .

A ball P of mass 2kg undergoes an elastic collision with another ball Q at rest. After collision, ball P continues to move in its original direction with a speed one-fourth of its original speed. What is the mass of ball Q ?

A collision in which there is absolutely no loss of K.E. is called an elastic collision. In such a collision, the linear momentum , total energy and kinetic energy, all are conserved.The coefficient of restitution // resilience of perfectly elastic collisions is unity. Read the above passage and answer the following questions : (i) When two bodies of equal masses undergo perfectly elastic collision in one dimension, what happens to their velocities ? (ii) How is this fact applied in a nuclear reactor ?

A ball of mass m moving with a velocity v undergoes an oblique elastic collision with another ball of the same mass m but at rest. After the collision if the two balls move with the same speeds , the angle between their directions of motion will be:

A 3 kg sphere makes an inelastic collision with another sphere at rest and they stick after the collision. If the composite mass moves with a speed of (1^(th))/(4) of the initial speed of 3 kg sphere, the mass of second sphere is

A particle P moving with speed v undergoes a head -on elastic collision with another particle Q of identical mass but at rest. After the collision the collision

In a head on elastic collision of two bodies of equal masses

A body of mass m is at rest. Another body of same mass moving with velocity V makes head on elastic collision with the first body. After collision the first body starts to move with velocity