During the reaction C6H12O6+6O2 to 6CO2+...

During the reaction `C_6H_12O_6+6O_2 to 6CO_2+6H_2O` which compound is reduced ?

Oxygen

Carbon dioxide

Glucose

Water

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Heat of reaction for, C_6H_(12)(s) + 6O_2(g) to 6 CO_2(g)+6H_2O(l) at constant pressure is -651 kcal at 17^@C . Calculate the heat of reaction at constant volume at 17^@C .

The standard entropy change for the reaction C_3H_(6(g)) + 9/2O_(2(g)) to 3CO_(2(g)) + 3H_2O_((l)) is – 339.23 JK-1 at 25^@C . Calculate the standard reaction enthalpy change if the standard Gibbs energy of formation of C_3H_(6(g)), CO_(2(g)) and H_2O_((l)) are 62.78, – 394.36 and –237.13 kJ. "mol"^(–1) respectively.

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The difference between the heats of reaction at constant pressure and a constant volume for the reaction 2C_6H_6(l)+15O_2(g)rarr12CO_2(g)+6H_2O(l) at 25^@C in kJ is

Calculate the standard enthalpy of reaction at 25^@C temperature for the following reaction : C_6H_6(I) + frac 15/2 O_2 (g) rarr 6CO_2(g)+3H_2O(I) . Given: The standard enthalpy of formation of C_6H_6(I) , .CO_2(g) and H_2O(I) are 49.0kJ mol^-1 , -393.5 kJ mol^-1 and -285.8 kJ mol^-1 respectively.

Calculate the standard enthalpy of reaction at 25^(@)C temperature for the following reaction: C_(6)H_(6)(l)+(15)/(2)O_(2)(g) to 6CO_(2)(g)+3H_(2)O(l) Given:The standard enthalpy of formation of C_(6)H_(6),CO_(2)(g) and H_(2)O(l) are 49.0 kJ *mol^(-1),-393.5kJ*mol^(-1) and -285.8kJ*mol^(-1) respectively.

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