When the temperature of a rod increases from 1 to t. Delta t,the moment of inertia increases from 1 to 1+Delta.The coefficient of linear expansion of the rod is alpha.The ratio Delta I/I is :

when the temperature of a body increses from t to t +Deltat ,its moment of inertia increases form I to I + DeltaI . The coefficient of linear expanison of the body is prop . The ratio (DeltaI)/I is equal to

When the temperature of a rod increases from t to t+Delta t , its moment of inertia increases from I to I+Delta I . If alpha is coefficient of linear expansion, the value of Delta I//I is

The moment of ineratia of a uniform thin rod about its perpendicular bisector is I . If the temperature of the rod is increased by Deltat , the moment of inertia about perpendicular bisector increases by (coefficient of linear expansion of material of the rod is alpha ).

The moment of inertia of a rod about its perpendicular bisector is I . When the temperature of the rod is increased by Delta T , the increase in the moment of inertia of the rod about the same axis is (Here , alpha is the coefficient of linear expansion of the rod )

A bimetallic strip is composed of two identical strips, one of steel and other of brass. When the temperature of the strip is raised by Delta T , it bends to form arc of curvature R. If the coefficients of linear expansion of steel and brass are alpha_1 and alpha_2 , respectively, then R is

If the temperature of a unifrom rod is slightly increased by Deltat , its moment of inertia I about a line parallel to itself will increase by