Home
Class 11
PHYSICS
A long horizontal slit is placed 1 mm ab...

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

Promotional Banner

Similar Questions

Explore conceptually related problems

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 in away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

Consider the situation of the previous problem, if the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen ?

In Young's double slit experiment, the widths of two slits are n the ratio 4 : 1 . The ratio of maximum and minimum intensity in the interference pattern will be :

The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

In Young’s double slit experiment, the intensity of light coming from the first slit is double the intensity from the second slit. The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is

In a Young's double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit-width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

The width of one of the two slits in a Young's double slit experiment is double of the other slit. Assuming that the amplitude of the light coming from a slit is proportional to the slit width, find the ratio of the maximum to the minimum intensity in the interference pattern.

A long narrow horizontal slit lies 1mm above a plane mirror.The interference pattern produced by the slit and its image is viewed on a screen distant 1m from the slit .The wavelength of light is 600nm .Find the distance of first maximum above the mirror.