The abscissae of two points A and B are the roots of the equation `x^(2)+2ax-b^(2)=0` and their ordinate are the roots fo the equations `y^(2)+2py-q^(2)=0` then the radius of the circle with AB as diameter is

The abscissa of the two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of the equation x^(2)+2px-q^(2)=0. Find the equation of the circle with AB as diameter.Also,find its radius.

The abscisae of A and B are the roots of the equation x ^(2) + 2ax -b ^(2) =0 and their ordinates are the roots of the equation y ^(2) + 2 py -q ^(2) =0. The equation of the circle with AB as diameter is

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.

STATEMENT-1 : The area of equilateral triangle inscribed in the circle x^(2) + y^(2) + 6x + 8y + 24 = 0 is (3sqrt(3))/(4) . STATEMENT-2 : The abscissae of two points A and B are the roots of the equation x^(2) + 3ax + b^(2) =0 and their ordinates are the roots of x^(2) + 3bx + a^(2) =0 Then the equation of the circle with AB as diameter is x^(2) + y^(2) + 3ax + 3by + a^(2) + b^(2) = 0 . STATEMENT-3 : If the circle x^(2) + y^(2) + 2gx + 2fx +c =0 always passes through exactly three quadrants not passing through origin then c gt 0 .

A abscissa of A and B are the roots of the equation x^2+2ax-b^2=0 and their ordinates are roots of the equation y^2+2py-q^2=0 . The equation of the circle with AB as diameter is

The abscissa of two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

The abscissae of two points Aand B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of y^(2)+2py-q^(2)=0 then the distance AB in terms of a,b,p,q is

The abscissa of two A and B are the roots of the equation x ^(2) - 4x - 6=0 and their ordinates are the roots of x ^(2) + 5x - 4=0. If r is the radius of circle with AB as diameter, then r is equal to