A ray of light incident at the point (-2, -1) gets reflected from the tangent at (0, -1) to the circle `x^2 +y^2=1`. The reflected ray touches the circle. The equation of the line along which the incident ray moved is

Statement I A ray of light incident at the point (-3,-1) gets reflected from the tangent at (0,-1) to the circle x^(2)+y^(2)=1 . If the reflected ray touches the circle, then equation of the reflected ray is 4y-3x=5 Statement II The angle of incidence = angle of reflection i.e. anglei=angler ,

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light passing through the point (8,3) gets reflected after it meets x -axis at (14,0) .Then the equation of the reflected ray

A ray of light incident along the line 3x+(5-4sqrt(2))y=15 gets reflected from the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 , then its reflected ray goes along the line

A light beam 2x+y+1=0 emanating from the point (-1,1) gets reflected from the straight line x+y+1=0 then reflected ray passes through

A ray of light is sent through the point P(1,2,3) and is reflected on the XY plane. If the reflected ray passes through the point Q(3,2,5) then the equation of the reflected ray is

A ray of light is sent through the point P(1, 2, 3,) and is reflected on the XY-plane. If the reflected ray passes through the point Q(3, 2, 5) , then the equation of the reflected ray is

A ray of light is sent from the point (-2020, -2019) along the line y = x +1. Upon reaching the line 2x + y -1= 0, the ray is reflected from it, then the equation of reflected ray is.

A ray of light is incident along a line which meets another line,7x-y+1=0, at the point (0,1). The ray isthen reflected from this point along the line,y+2x=1. Then the equation of the line of incidence of the ray of light is (A) 41x+38y-38=0 (B) 41x-38y+38=0( C) 41x+25y-25=0 (D) 41x-25y+25=0