If a line passes through the point `P(1,-2)` and cuts the `x^2+y^2-x-y= 0`at `A` and `B`, then the`maximum of `PA+PB` is

If a line passes through the point P(1,-2) and cuts the x^2+y^2-x-y= 0at A and B, then themaximum of PA+PB is

A line passing through the points A(1.-2) cuts the circle x^(2)+y^(2)-y=0 at P and Q Then the maximum value of |AP-AQ| is

A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

A line drawn through the point P(4,7) cuts the circle x^(2)+y^(2)=9 at the points A and B .Then PA.PB is equal to:

If a line with positive slope passing through point P(0,1) interesects the curve y=x^(2)-x at A and B such that PA.PA=2, then AB is:

Find the equation of the line passing through the point P(1,2) cutting the lines x+y-5=0 and 2x-y=7 at A and B respectively such that the H.M. of PA and PB is 10.(A,B lie on the same side of P)

If a line through P(-2,3) meets the circle x^(2)+y^(2)-4x+2y+k=0 at A and B such that PA.PB =31 then the radius of the circle is

A line passes through the point P (5,6) outside the circle x^(2) + y ^(2) = 12 and meets the circle at A and B. The value of PA. PB is equal to