" A freely falling body takes "' second to travel first "(1/x)^(th)" distance.Then,time of descent is "

A freely falling body takes T second to travel first (1/x)th distance.Then,time of descent is

A freely falling body takes 't' second to travel first 1/xth distance.Then,time of descent is

A freely falling body takes t second to travel (1//x)^(th) distance then time of descent is

For a freely falling body

What is a freely falling body ?

A freely falling body travels-- of total distance in 5th second

The KE of a freely falling body

If a freely falling body travels in the last second, a distance equal to the distance travelled by it in the first three second, the time of the travel is

A freely falling body travelled x m in n^("th") second. Then distance travelled in n-1^("th") second is