I am a 2 digit number.
The digit. in tens place and the digit in units place are consecutive prime numbers. The sum of digits is multiple of 3 and 4. The number is

Options

A. 57
B. 23
C. 35
D. 13

Answer

To solve the problem step by step, we will follow these guidelines:

1. **Identify the properties of the number**: We know that it is a two-digit number, and the digits in the tens and units places are consecutive prime numbers. Additionally, the sum of the digits must be a multiple of both 3 and 4.

2. **List the two-digit numbers**: The two-digit numbers range from 10 to 99.

3. **Identify consecutive prime numbers**: The prime numbers less than 10 are 2, 3, 5, and 7. The consecutive pairs of these primes are (2, 3), (3, 5), and (5, 7).

4. **Form two-digit numbers from these pairs**:
- From (2, 3): The possible number is 23.
- From (3, 5): The possible number is 35.
- From (5, 7): The possible number is 57.

5. **Calculate the sum of the digits for each number**:
- For 23: \(2 + 3 = 5\)
- For 35: \(3 + 5 = 8\)
- For 57: \(5 + 7 = 12\)

6. **Check if the sums are multiples of 3 and 4**:
- For 23: 5 is not a multiple of 3 or 4.
- For 35: 8 is not a multiple of 3 but is a multiple of 4.
- For 57: 12 is a multiple of both 3 and 4.

7. **Conclusion**: The only number that satisfies all the conditions is 57.

### Final Answer:
The number is **57**.