Home
Class 14
MATHS
How much area of metal sheet is rquired ...

How much area of metal sheet is rquired to make an open cylindrical tank of radius 3.5 m and height of 12 m ?

A

`305m^(2)`

B

`285m^(2)`

C

`292 . 7m^(2)`

D

`302.5m^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the metal sheet required to make an open cylindrical tank, we need to calculate the total surface area of the cylinder. The formula for the total surface area of an open cylinder (which does not have a top) is given by: \[ \text{Total Surface Area} = 2\pi rh + \pi r^2 \] Where: - \( r \) is the radius of the cylinder - \( h \) is the height of the cylinder - \( \pi \) is a constant approximately equal to \( \frac{22}{7} \) ### Step 1: Identify the given values - Radius \( r = 3.5 \) m - Height \( h = 12 \) m ### Step 2: Substitute the values into the formula We will substitute the values of \( r \) and \( h \) into the total surface area formula: \[ \text{Total Surface Area} = 2\pi(3.5)(12) + \pi(3.5)^2 \] ### Step 3: Calculate the lateral surface area First, calculate the lateral surface area \( 2\pi rh \): \[ 2\pi(3.5)(12) = 2 \times \frac{22}{7} \times 3.5 \times 12 \] Calculating this step-by-step: 1. Calculate \( 2 \times \frac{22}{7} = \frac{44}{7} \) 2. Now calculate \( \frac{44}{7} \times 3.5 \): - \( 3.5 = \frac{35}{10} = \frac{35}{10} = \frac{35 \times 10}{10 \times 10} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} = \frac{350}{100} \) - \( \frac{44 \times 35}{7 \times 10} = \frac{1540}{70} = 22 \) 3. Finally, multiply by 12: - \( 22 \times 12 = 264 \) So, the lateral surface area is \( 264 \) m². ### Step 4: Calculate the area of the base Now calculate the area of the base \( \pi r^2 \): \[ \pi(3.5)^2 = \frac{22}{7} \times (3.5 \times 3.5) = \frac{22}{7} \times 12.25 \] Calculating this step-by-step: 1. Calculate \( 3.5 \times 3.5 = 12.25 \) 2. Now calculate \( \frac{22 \times 12.25}{7} = \frac{269.5}{7} = 38.5 \) So, the area of the base is \( 38.5 \) m². ### Step 5: Add the lateral surface area and the base area Now, add the lateral surface area and the base area to get the total surface area: \[ \text{Total Surface Area} = 264 + 38.5 = 302.5 \text{ m}^2 \] ### Final Answer The area of the metal sheet required to make the open cylindrical tank is \( \text{302.5 m}^2 \). ---
Promotional Banner

Similar Questions

Explore conceptually related problems

How much metal sheet is required to prepare a cylindrical pipe 10 cm long and radius 7 cm?

Find the area of metal sheet required in making a closed hollow cone of base radius 7cm and height 24cm.

A rectangular water tank of base 11 m xx 6m contains water upto a height of 5 m. If the water in the tank is transferred to a cylindrical tank of radius 3.5 m, find the height of the water level in the tank.

How much cloth 2.5 m wide will be required to make a conical tent having base radius 7 m and height 24 m ?

A rectangular water tank of base 11 m xx 6 m contains water up to a height of 5 m. If the water in the tank is transferred to a cylindrical tank of radius 1.75 m, find the height of the water level in the tank.

Find the capacity of a cylindrical vessel, whose radius is 3m. and height 7m.

What is the area of a ground that can be levelled by a cylindrical roller of radius 3.5 m and 4 m long by making 10 rounds?

Find the time required for a cylindrical tank of radius 2.5m and height 3m to empty through a round hole of 2.5cm with a velocity 2.5sqrt(h)m/s,h being the depth of the water in the tank.

How many square metres of canvas is required for a conical tent whose height is 3.5 m and the radius of the base is 12 m ?