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If we increased 20% in numerator and 25%...

If we increased 20% in numerator and 25% in denominator of a fraction, then it is `3/5` then the original fraction is:

A

`8/5`

B

`5/8`

C

`3/8`

D

`8/3`

Text Solution

AI Generated Solution

The correct Answer is:
To find the original fraction given that increasing the numerator by 20% and the denominator by 25% results in the fraction \( \frac{3}{5} \), we can follow these steps: ### Step 1: Define the Original Fraction Let the original fraction be \( \frac{n}{d} \), where \( n \) is the numerator and \( d \) is the denominator. ### Step 2: Apply the Percentage Increases According to the problem, if we increase the numerator by 20%, the new numerator becomes: \[ n + 0.2n = 1.2n \] Similarly, if we increase the denominator by 25%, the new denominator becomes: \[ d + 0.25d = 1.25d \] ### Step 3: Set Up the Equation The problem states that the new fraction is equal to \( \frac{3}{5} \): \[ \frac{1.2n}{1.25d} = \frac{3}{5} \] ### Step 4: Cross-Multiply to Eliminate the Fraction Cross-multiplying gives us: \[ 5 \cdot 1.2n = 3 \cdot 1.25d \] This simplifies to: \[ 6n = 3.75d \] ### Step 5: Simplify the Equation Dividing both sides by 3 gives: \[ 2n = 1.25d \] Now, we can express \( n \) in terms of \( d \): \[ n = \frac{1.25}{2}d = 0.625d \] ### Step 6: Write the Original Fraction Now we can write the original fraction \( \frac{n}{d} \): \[ \frac{n}{d} = \frac{0.625d}{d} = 0.625 \] To express this as a fraction, we can convert 0.625 into a fraction: \[ 0.625 = \frac{625}{1000} = \frac{5}{8} \] ### Conclusion Thus, the original fraction is: \[ \frac{5}{8} \]

To find the original fraction given that increasing the numerator by 20% and the denominator by 25% results in the fraction \( \frac{3}{5} \), we can follow these steps: ### Step 1: Define the Original Fraction Let the original fraction be \( \frac{n}{d} \), where \( n \) is the numerator and \( d \) is the denominator. ### Step 2: Apply the Percentage Increases According to the problem, if we increase the numerator by 20%, the new numerator becomes: \[ ...
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