A person boarded an express train on 29th November, 2019 at Surat (Gujarat) for Nagarcoil (Kerala). The train departed from Surat at 19:45 hours and reached Nagarcoil at 11:45 hours on 1st December, 2019. If the distance between Surat and Nagarcoil by train route is nearly 2120 km, the average speed of the train during the journey was

Options

A. (a) 132.5 km/h
B. (b) 60 km/h
C. (c) 53 km/h
D. (d) 45 km/h

Answer

C

Explanation

Time for travel on 29th November = (24:00-19:45)= 4:15 hr 
Time for travel on 30th November = 24 hrs
Time for travel on 1st December = 11:45 hrs
Total time taken for travel by express train from Surat to Nagarcoil
 = 4:15 + 24:00 +11:45 = 40 hrs
Total covered distance for travel by express train from Surat to Nagarcoil = 2120 km 
`therefore` Average speed of train
`= ("Total covered distance")/("Total time") = (2120)/(40)` km/hrs