Electric flux through closed surface

Electric flux through a closed surface in free space enclosing a charge q is

A closed surface encloses a net charge of -3.60 muC . What is the net electric flux through the surface? (b) The electric flux through a closed surface is found to be 780 N-m^2//C . What quantity of charge is enclosed by the surface? (c) The closed surface in part (b) is a cube with sides of length 2.50 cm. From the information given in part (b), is it possible to tell where within the cube the charge is located? Explain.

Which of the following statements is//are correct? a. Electric field calculated by Gauss law is the field due to only those charges which are enclosed inside the Gaussian surface. b. Gauss law is applicable only when there is a symmetrical distribution of charge. c. Electric flux through a closed surface is equal to total flux due to all the charges enclosed within that surface only.

The electric flux through a chlosed surface area S enclosing charge Q is phi . If the surface area is doubled, then the flux is

Which of the following law gives a relation between the electric flux through any closed surface and the charge enclosed by the surface ?

The total electric flux through any closed surface from gauss law is given by ?

Assertion : The magnetic flux through a closed surface containing a bar magnet is zero. Reason : Gauss's law applies in the case of electric flux only.

If the flux of the electric field through a closed surface is zero,