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shows an oscillating pendulum. Time...

shows an oscillating pendulum.

Time taken by the bob to move from A to C is `t_(1)` and from C to O is `t_(2)`. The time period of this simple pendulum is

A

`(t_(1)+t_(2))`

B

`2(t_(1)+t_(2))`

C

`3(t_(1)+t_(2))`

D

`4(t_(1)+t_(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
A point mass attached to a light inextensible string and suspended from fixed support is called a simple pendulum. The vertical line passing through the fixed support is the mean position of a simple pendulum. The time period of oscillation of a wave is defined as the time taken by any element of the string to complete one such oscillation. A pendulum clock takes 1 s to move from one extreme to the other extreme. As a result, one oscillation takes 2 seconds. The total time taken by the bob to move from A to 0 is (t1+ t2) which is 1/4th time of one full cycle of the pendulum. A time period of pendulum i.e. time taken by pendulum to complete one oscillation from A to B and back to A will be 4 (t1 + t2).
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