A regular pentagon ABCDE and a square ABFG are formed on opposite sides of AB. Find `angle`BCF.

In the given figure, ABCD is a square . EFGH is a square formed by joining mid points of sides of ABCD, LMNO is a square formed by joining mid point of sideds of EFGH . A circle is inscribed inside EFGH . If area of circle is 38 . 5 cm^(2) , then what is the area (in cm^(2) ) of square ABCD ?

ABCDE is a regular pentagon. The bisector of angle A meets the side CD at M. Find angle AMC

In the given figure, ABCD is a square, BCXYZ is a regular pentagon and ABE is an equilateral triangle. What is the value (in degrees) of angleEBZ ?

In the given figure , ABCD is a square BCXYZ is a regular pentagon and ABE is an equilateral triangle . What is the value (in degrees) of angle EBZ ?

ABCD is a square. Find out the side of square?

ABCDE is a regular pentagon. Its sides are extended as shown in the figure. The value of (angleABC + 2angleEGD + 3angleBAJ)/6 is:

A wire of length 20 is cut into two parts one is made into regular hexagon of side a and other to square . Find a if combined area of square and regular hexagon is minimum

ABCDE is a regular pentagon. Angle bisector of angle BAE meets CD at m. angle bisector of angle BCD meets AM at P. Find the angle CPM = ?