In `∆PQR`, if 3`∠P = 4∠Q = 6∠R`, calculate the angles of the triangle.

Let O be the origin, and O X x O Y , O Z be three unit vectors in the direction of the sides Q R , R P , P Q , respectively of a triangle PQR. If the triangle PQR varies, then the minimum value of cos(P+Q)+cos(Q+R)+cos(R+P) is: -3/2 (b) 5/3 (c) 3/2 (d) -5/3

If the vertices P,Q and R of a triangle have cooddinates (2,3,5),(-1,3,2) and (3,5,-2) respectively,then find the angles of the triangle PQR.

If the vertices P,Q and R of a triangle have cooddinates (2,3,5),(-1,3,2) and (3,5,-2) respectively,then find the angles of the triangle PQR.

In Delta PQR , If angle R gt angle Q, then

Let O(0, 0), P(3, 4), Q(6, 0) be the vertices of the triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR, PQR are of equal area. The coordinates of R are

In a Delta PQR. if 3sin P+4cos Q=6 and 4sin Q+3cos P=1, then the angle R is equal to:

In /_PQR if 3sin P+4cos Q=6 and 4sin Q+3cos P=1 then the angle R is equal to