`(3)/(5) = (square)/(20)`

Replace square by the correct number in each of the follwing: (i) (2)/(7)=(8)/(square) (ii) (3)/(5)=(square)/(35) (iii) (5)/(8)=(20)/(square) (iv) (45)/(60)=(9)/(square) (v) (40)/(56)=(square)/(7) (vi) (42)/(54)=(7)/(square)

Fill in the place holders: a. (24)/(40)= (square)/(5)= (12)/(square) b. (36)/(63)= (4)/(square)= (square)/(21) c. (5)/(7)= (square)/(28)= (35)/(square)

fill in the boxes with the correct symbol >, (3)/(7) square (-5)/(6)

Fill in the place holders with the correct symbol > or (i) (8)/(9)square(5)/(9) (ii) (9)/(10)square(7)/(10) (iii) (3)/(7)square(6)/(7) (iv) (11)/(15)square(8)/(15) (v) (6)/(11)square(5)/(11) (vi) (11)/(20)square(17)/(20)

Simplify ((3)/(5))-((7)/(20))

Fill appropriate sign: (a) 1/2 square1/5 (b) 2/4 square 3/6 (c) 3/5 square 2/3 (d) 3/4 square 2/8 (e) 3/5 square 6/5 (f) 7/9 square 3/9

Write the proper number in the empty boxes : 22/40=11/20=(11xxsquare)/(20xxsquare)=square/100=square

Complete the following activity to solve simultaneous equations : 4x+ 3y = 18 " "...(1) 5x - 3y = 9 " " ...(2) Adding equations (1) and (2) , +{:(4x+3y=18" ...(1)"),(5x-3y=9" ...(2)"),(bar(squarex" "=square)):} :. X = (square)/(square ) " " :. X = square Substituting x = 3 in equation (1) , 4 xx square + 3y = 18 " " :. 3y = 18 - square " " :. 3y = square :. y = 2 (x,y ) = (square, square ) is the solution

If p/q = 5/7 then (3p)/(4q) =square

Mean of x= 25 Mean of y =20 sigma_x = 4 sigma_y=3 r = 0.5 b_(yx) = square b_(xy)= square When x = 10 y-square=square(10 - square) :. y = square