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An element X with an atomic mass of 60 "...

An element X with an atomic mass of 60 `"g mol"^(-1)` has density of 6.23`"g cm"^(-3)` . If the edge length of its cubic unit cell is 400 pm, identify the cubic unit cell. Calculate the radius of an atom of this element.

Text Solution

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We use the relationship,
`d=ZM//(a^(3) xx N_(A))`
where, Z is the unknown, substitute all the given values of d, M, a and Ny to get the answer, Z = 4
Since, Z = 4, the type of cubic unit is face centred cubic cell.
For fcc, we know, `r=a//(2sqrt(2))`
Substituting the value of a, we get r = 141.4 pm.
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